1
For positive integers n, if 4an = (n2 + 5n + 6 ) and Sn = k=1n ( 1ak ), then the value of 507S2025 is :
- 540
- 675
- 1350
- 135
Answer
(2) 675
Solution
an = (n + 2)(n + 3)4
1ak = 4(k + 2)(k + 3) = 4 ( 1k + 2 - 1k + 3 )
Sn = 4 ( 13 - 1n + 3 ) (telescoping)
S2025 = 4 ( 13 - 12028 ) = 4 676 - 12028 = 4 6752028
507S2025 = 507 4 6752028
= 675 (as 2028 = 4 507)
Answer: (2)
JEE Main 2025 (Online) 28th January Evening Shift