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Sequences and Series · Question 51

JEE Main 2025 (Online) 28th January Evening ShiftNumericalEasy📈 Topic in 55% papers+4
1

The interior angles of a polygon with n sides are in an A.P. with common difference 6 . If the largest interior angle of the polygon is 219 , then n is equal to .

Answer

20

Solution

Taking the angles from the largest, they form an A.P. with first term 219 and common difference -6 .

Sum = n2[2(219) - 6(n - 1)] = n(222 - 3n)

Sum of interior angles = (n - 2) 180

222n - 3n2 = 180n - 360

3n2 - 42n - 360 = 0

n2 - 14n - 120 = 0

(n - 20)(n + 6) = 0 n = 20

(Check: smallest angle = 219 - 19 6 = 105 > 0.)

Answer: 20

JEE Main 2025 (Online) 28th January Evening Shift

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2

Let =3+4+8+9+13+14+ upto 40 terms. If ( ) 1020 is a root of the equation x2+x-2=0, (0, 2 ), then 2 +3 2 is equal to :

  1. 2
  2. 74
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  4. 32
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3

The value of 13-23+33- +153 is :

  1. 1706
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  3. 1982
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4

The sum of the first ten terms of an A.P. is 160 and the sum of the first two terms of a G.P. is 8. If the first term of the A.P. is equal to the common ratio of the G.P. and the first term of the G.P. is equal to common difference of the A.P., then the sum of all possible values of the first term of the G.P. is :

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5

For the functions f( )= 2 + 2 , and g( )= 2 + 2 , > >0, let 0< < 2 f( )= 0< < g( ). If the first term of a G.P. is ( 2 ), its common ratio is ( 2 ) and the sum of its first 10 terms is mn, (m, n)=1, then m+n is equal to .

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6

Consider the quadratic equation (n2-2n+2 )x2-3x+ (n2-2n+2 )2=0, n R. Let be the minimum value of the product of its roots and be the maximum value of the sum of its roots. Then the sum of the first six terms of the G.P., whose first term is and the common ratio is , is :

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7

The sum 1+ 12 (12+22 )+ 13 (12+22+32 )+ upto 10 terms is equal to :

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  2. 155
  3. 3152
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8

Let the sum of the first n terms of an A.P. be 3n2+5n. Then the sum of squares of the first 10 terms of the A.P. is:

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9

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  1. 65
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10

If the sum of the first 10 terms of the series 11+14 4+ 21+24 4 + 31+34 4+ 41+44 4+ is mn, (m, n)=1, then m+n is equal to :

  1. 256
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11

Let A1, A2, A3, , A39 be 39 arithmetic means between the numbers 59 and 159. Then the mean of A25, A28, A31 and A36 is equal to :

  1. 129
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