In the circuit shown, if a conducting wire is connected between points A and B, the current in this wire will [figure]
- flow from B to A
- flow from A to B
- flow in the direction which will be decided by the value of V
- be zero
Answer
(1) flow from B to A
Solution
The long plate (positive terminal) of the battery is on the left, so take the left junction at potential V and the right junction at 0.
Upper arm (4 Ω + 4 Ω): VA = V - 44 + 4V = V2
Lower arm (1 Ω + 3 Ω): VB = V - 11 + 3V = 3V4
VB > VA (the bridge is unbalanced: 44 13)
current in the wire flows from B to A.
Answer: (1)