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Power dissipated across the 8 Ω resistor in the circuit shown here is 2 watt. The power dissipated in watt units across the 3 Ω resistor is [figure]
(1) 3.0
For the 8 Ω resistor: P = i22 R 2 = i22 8 i2 = 0.5 A
p.d. across the parallel combination V = i2 8 = 4 V
Upper branch (1 Ω + 3 Ω = 4 Ω): i1 = 44 = 1 A
Power in 3 Ω = i12 3 = 12 3 = 3.0 W
Answer: (1)
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