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The value of - 2y(1 + y)1 + 2 y dy is :
(2) 2
2y1 + 2 y is odd and 2y y1 + 2 y is even
I = 0 + 2 0 2y y1 + 2 y dy = 4 0 y y1 + 2 y dy
0 y f( y) dy = 2 0 f( y) dy (put y - y and add)
I = 2 0 y1 + 2 y dy
= 2 [- -1( y) ]0
= 2 ( 4 + 4 ) = 2
Answer: (2)
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