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If the value of the integral -11 x1 + 3x dx is 2 , then a value of is
(1) 2
I = -11 x1 + 3x dx
Put x -x ( -aaf(x) dx = -aaf(-x) dx ): I = -11 3x x3x + 1 dx
Adding: 2I = -11 x dx = 2
= 2
= 2 satisfies it: ( /2) /2 = 2
Answer: (1)
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