The sum of all values of [0,2 ] satisfying 2 2 = 2 and 2 2 =3 is
- 5 6
- 2
- 4
Answer
(1)
Solution
2 2 =1-2 2 = 12
2 2 =3 (2 -1)( +2)=0 = 12
[figure]
Common solutions: the two points where the line y= 12 cuts the circle: = 6, 5 6
Sum =
Answer: (1)
The sum of all values of [0,2 ] satisfying 2 2 = 2 and 2 2 =3 is
(1)
2 2 =1-2 2 = 12
2 2 =3 (2 -1)( +2)=0 = 12
[figure]
Common solutions: the two points where the line y= 12 cuts the circle: = 6, 5 6
Sum =
Answer: (1)
Let S= \ (-2 , 2 ) : +1= 3 \. Then S is equal to :
Let A, B, where A, B (- 2, 2 ), be the roots of the quadratic equation x2-2x-5=0. Then 20 2 ( A+B2 ) is equal to :
The sum of all the integral values of p such that the equation 3 2 x+12 x-3=p, x R, has at least one solution, is:
If S= \ [- , ] : . . 5 2= 7 7 2 \, then n(S) is equal to .
If A= 3 9 + 9 27 + 27 81 and B= 81 - 3 , then BA is equal to .
If ( 18 ) ( 5 18 ) ( 7 18 )=K, then the value of ( 10K 3 ) is :
Let S=\x [- , ] : x( x+ x)=a, a Z\. Then n(S) is equal to :
Let P=\ [0, 4 ] : 2 1\ and S=\a Z : 2( 8 - 8 ) 2 =a2, P\. Then n(S) is:
If (A - B) A + 2 C 2 A = 1, A, B, C (0, 2 ), then
The sum of all the elements in the range of f(x) = Sgn( x) + Sgn( x) + Sgn( x) + Sgn( x), x n 2, n Z, where Sgn(t) = cases 1, & if t > 0 \ -1, & if t < 0 cases is :