A cup of coffee cools from 90 to 80 in t minutes, when the room temperature is 20 . The time taken by a similar cup of coffee to cool from 80 to 60 at a room temperature same at 20 is :
- 513t
- 1310t
- 135t
- 1013t
Answer
(3) 135t
Solution
Newton's law of cooling (average form): T1 - T2t = K ( T1 + T22 - T0 )
Case 1: 90 - 80t = K(85 - 20) 10t = 65K ...(i)
Case 2: 80 - 60t' = K(70 - 20) 20t' = 50K ...(ii)
Dividing (ii) by (i): 20t' t10 = 5065
t' = 2 6550 t = 135 t
Answer: (3)