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Chemical Bonding and Molecular Structure · Question 3

JEE Advanced 2026 Paper 2MCQEasy📈 Topic in 17% papers+4−1
1

The correct order of ONO bond angle in the given species is

  1. NO2+<NO2<NO3-<NO2-
  2. NO2-<NO3-<NO2<NO2+
  3. NO3-<NO2-<NO2<NO2+
  4. NO2-<NO3-<NO2+<NO2

Answer

(2) NO2-<NO3-<NO2<NO2+

Solution

Bond angle depends on hybridisation and on the repulsion by the non-bonding electrons on N.

NO2+: sp, linear, 180 .

NO2: sp2 with only one odd electron on N (weak repulsion), about 134 .

NO3-: sp2, trigonal planar, 120 .

NO2-: sp2 with a full lone pair on N, about 115 .

Order: NO2-<NO3-<NO2<NO2+

Answer: (B)

JEE Advanced 2026 Paper 2

Keep practising — Chemical Bonding and Molecular Structure

2

Regarding the molecular orbital (MO) energy levels for homonuclear diatomic molecules, the INCORRECT statement(s) is(are)

  1. Bond order of Ne2 is zero.
  2. The highest occupied molecular orbital (HOMO) of F2 is σ-type.
  3. Bond energy of O2+ is smaller than the bond energy of O2.
  4. Bond length of Li2 is larger than the bond length of B2.
JEE Advanced 2025 Paper 1
3

The option(s) in which at least three molecules follow Octet Rule is(are)

  1. CO2, C2H4, NO and HCl
  2. NO2, O3, HCl and H2SO4
  3. BCl3, NO, NO2 and H2SO4
  4. CO2, BCl3, O3 and C2H4
JEE Advanced 2024 Paper 1

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