A parallel plate air capacitor has a capacitance C. When it is half filled as shown in figure with a dielectric constant K=5, the percentage increase in the capacitance is . [figure]
- 33.34
- 66.67
- 200
- 400
Answer
(2) 66.67
Solution
[figure]
Air-filled: C= 0Ad
Slab (K, thickness d/2): C1= K 0Ad/2=2KC
Air gap (thickness d/2): C2= 0Ad/2=2C
C1 and C2 are in series:
C'= C1C2C1+C2= 2KC 2C2KC+2C= 2KK+1C
C'= 2 55+1C= 53C
Percentage increase = C'-CC 100= 23 100
=66.67\%
Answer: (2)