Two point charges of 1 nC and 2 nC are placed at the two corners of equilateral triangle of side 3 cm. The work done in bringing a charge of 3 nC from infinity to the third corner of the triangle is . 14 0 = 9 109 N m2/C2
- 3.3
- 27
- 2.7
- 5.4
Answer
(3) 2.7
Solution
Potential at the third corner due to the two charges (each at r = 0.03 m):
V = 14 0 q1 + q2r = 9 109 3 10-90.03 = 900 V
W = qV = 3 10-9 900 = 2.7 10-6 J
W = 2.7
Answer: (3)