The space between the plates of a parallel plate capacitor of capacitance C (without any dielectric) is now filled with three dielectric slabs of dielectric constants K1 = 2, K2 = 3 and K3 = 5 (as shown in figure). If new capacitance is n3C then the value of n is . [figure]
Answer
8
Solution
C = 0 Ad
Upper slab K1 (area A, thickness d2): C1 = K1 0 Ad/2 = 2K1C = 4C
Lower half: K2 and K3 side by side (each of area A2, thickness d2) are in parallel:
C23 = K2 0 (A/2)d/2 + K3 0 (A/2)d/2 = (K2 + K3)C = 8C
C1 and C23 are in series:
C' = C1 C23C1 + C23 = 4C 8C12C = 83C
n = 8
Answer: 8