A circular table is rotating with an angular velocity of rad/s about its axis (see figure). There is a smooth groove along a radial direction on the table. A steel ball is gently placed at a distance of 1 m on the groove. All the surfaces are smooth. If the radius of the table is 3 m, the radial velocity of the ball w.r.t. the table at the time ball leaves the table is x 2 m/s, where the value of x is . [figure]
Answer
2
Solution
In the table's frame the only radial force is the centrifugal force m 2r (groove is smooth).
v dvdr = 2r
0v v dv = 2 13 r dr
v22 = 22(32 - 12) = 4 2
v = 2 2 m/s
x = 2
Answer: 2