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Integrals · Question 43

JEE Main 2025 (Online) 3rd April Evening ShiftMCQMedium📈 Topic in 71% papers+4−1
1

The integral 0 8x dx4 2 x + 2 x is equal to

  1. 2 2
  2. 4 2
  3. 2
  4. 3 22

Answer

(1) 2 2

Solution

I = 0 8x4 2 x + 2 xdx

Using 0a f(x) dx = 0a f(a - x) dx:

I = 0 8( - x)4 2 x + 2 xdx

2I = 8 0 dx4 2 x + 2 x

I = 4 2 0 /2 dx4 2 x + 2 x (integrand symmetric about 2)

= 8 0 /2 2 x dx4 + 2 x

Put x = t:

I = 8 0 dt4 + t2 = 8 12 [ -1 t2 ]0

= 4 2 = 2 2

Answer: (1)

JEE Main 2025 (Online) 3rd April Evening Shift

Keep practising — Integrals

2

Let [.] denote the greatest integer function. If 0e3 [ 1ex-1 ] dx = - e 2, then 3 is equal to .

JEE Main 2025 (Online) 2nd April Morning Shift
3

Let (a, b) be the point of intersection of the curve x2 = 2y and the straight line y - 2x - 6 = 0 in the second quadrant. Then the integral I = ab 9x21 + 5x dx is equal to :

  1. 27
  2. 18
  3. 24
  4. 21
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4

4 01 ( 1 3 + x2 + 1 + x2 )dx - 3 e( 3) is equal to :

  1. 2 - 2 - e(1 + 2)
  2. 2 + 2 + e(1 + 2)
  3. 2 + 2 - e(1 + 2)
  4. 2 - 2 + e(1 + 2)
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5

The integral 80 0 4 ( + 9 + 16 2 )d is equal to :

  1. 3 4
  2. 4 3
  3. 6 43
  4. 2 3
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6

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  1. 196
  2. 100
  3. 64
  4. 144
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7

Let f: R R be a twice differentiable function such that f(2) = 1. If F(x) = x f(x) for all x R, 02 x F'(x) dx = 6 and 02 x2 F''(x) dx = 40, then F'(2) + 02 F(x) dx is equal to:

  1. 13
  2. 11
  3. 9
  4. 15
JEE Main 2025 (Online) 28th January Evening Shift
8

If f(x) = 1x1/4 (1 + x1/4 )dx, f(0) = -6, then f(1) is equal to :

  1. 4 ( e 2 - 2 )
  2. e2 2 + 2
  3. 2 - e2
  4. 4 ( e 2 + 2 )
JEE Main 2025 (Online) 28th January Evening Shift
9

Let f be a real valued continuous function defined on the positive real axis such that g(x) = 0x t f(t) dt. If g (x3 ) = x6 + x7, then value of r=115 f (r3 ) is :

  1. 270
  2. 340
  3. 310
  4. 320
JEE Main 2025 (Online) 28th January Evening Shift

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