Number of moles of H+ ions required by 1 mole of MnO4- to oxidise oxalate ion to CO2 is .
Answer
8
Solution
2MnO4- + 5C2O42- + 16H+ 2Mn2+ + 10CO2 + 8H2O
∵ Mn: +7 → +2 (gains 5e-); C2O42- 2CO2 (loses 2e-)
⇒ MnO4- : C2O42- = 2 : 5
2 mol MnO4- need 16 mol H+ ⇒ 1 mol needs 8 mol
Answer: 8