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Complex Numbers and Quadratic Equations · Question 6

JEE Advanced 2024 Paper 1NumericalEasy📈 Topic in 33% papers+4
1

Let f(x)=x4+ax3+bx2+c be a polynomial with real coefficients such that f(1)=-9. Suppose that i 3 is a root of the equation 4x3+3ax2+2bx=0, where i= -1. If 1, 2, 3, and 4 are all the roots of the equation f(x)=0, then | 1|2+| 2|2+| 3|2+| 4|2 is equal to .

Answer

20

Solution

4x3+3ax2+2bx=x(4x2+3ax+2b) has real coefficients, so i 3 are roots of 4x2+3ax+2b=0.

4x2+3ax+2b=4(x2+3) a=0, b=6

f(1)=1+6+c=-9 c=-16

f(x)=x4+6x2-16=(x2+8)(x2-2), roots 2 2i, 2

Sum of | k|2=8+8+2+2=20

Answer: 20

JEE Advanced 2024 Paper 1

Keep practising — Complex Numbers and Quadratic Equations

2

Match each entry in List-I to the correct entry in List-II and choose the correct option.

  1. (P) → (1), (Q) → (2), (R) → (5), (S) → (4)
  2. (P) → (3), (Q) → (1), (R) → (4), (S) → (5)
  3. (P) → (1), (Q) → (2), (R) → (4), (S) → (5)
  4. (P) → (2), (Q) → (3), (R) → (5), (S) → (4)
JEE Advanced 2026 Paper 1
3

Let a, b, c be positive integers in arithmetic progression such that the equation ax2+bx+c=0 has only integer solutions. Then which of the following statements is (are) TRUE ?

  1. c-b is an integer multiple of a
  2. Both the roots of the equation ax2+bx+c=0 are odd integers
  3. If c=15, then ab=8
  4. If b=8, then x=3 is a root of the equation ax2+bx+c=0
JEE Advanced 2026 Paper 2
4

Let R denote the set of all real numbers. Let ai, bi R for i \1, 2, 3\. Define the functions f: R R, g: R R, and h: R R by f(x) = a1 + 10x + a2x2 + a3x3 + x4, g(x) = b1 + 3x + b2x2 + b3x3 + x4, h(x) = f(x+1) - g(x+2). If f(x) g(x) for every x R, then the coefficient of x3 in h(x) is

  1. 8
  2. 2
  3. -4
  4. -6
JEE Advanced 2025 Paper 1
5

Let R denote the set of all real numbers. Let z1 = 1 + 2i and z2 = 3i be two complex numbers, where i = -1. Let S = \(x, y) R R : |x + iy - z1| = 2|x + iy - z2|\. Then which of the following statements is (are) TRUE?

  1. S is a circle with centre (- 13, 103 )
  2. S is a circle with centre ( 13, 83 )
  3. S is a circle with radius 23
  4. S is a circle with radius 2 23
JEE Advanced 2025 Paper 1
6

For a non-zero complex number z, let (z) denote the principal argument of z, with - < (z) . Let be the cube root of unity for which 0< ( )< . Let = ( n=12025(- )n ). Then the value of 3 is .

JEE Advanced 2025 Paper 2

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