Let f(x)=x4+ax3+bx2+c be a polynomial with real coefficients such that f(1)=-9. Suppose that i 3 is a root of the equation 4x3+3ax2+2bx=0, where i= -1. If 1, 2, 3, and 4 are all the roots of the equation f(x)=0, then | 1|2+| 2|2+| 3|2+| 4|2 is equal to .
Answer
20
Solution
4x3+3ax2+2bx=x(4x2+3ax+2b) has real coefficients, so i 3 are roots of 4x2+3ax+2b=0.
4x2+3ax+2b=4(x2+3) a=0, b=6
f(1)=1+6+c=-9 c=-16
f(x)=x4+6x2-16=(x2+8)(x2-2), roots 2 2i, 2
Sum of | k|2=8+8+2+2=20
Answer: 20