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A charge of 4.0 is moving with a velocity of 4.0 106 ms-1 along the positive y axis under a magnetic field B of strength (2 k) T. The force acting on the charge is x i N. The value of x is .
32
F=q ( v B )
=4 10-6 (4 106 j 2 k )
=32 ( j k)
∵ j k= i ⇒ F=32 i N
x=32
Answer: 32
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