The magnetic field at the centre of a wire loop formed by two semicircular wires of radii R1=2 m and R2=4 m, carrying current I=4 A as per figure given below is 10-7 T. The value of is . (Centre O is common for all segments) [figure]
Answer
3
Solution
Straight parts lie along lines through O they give no field at O.
A semicircle of radius R gives B= 0I4R at its centre.
Going round the loop, both semicircles carry current in the same sense about O, so their fields add.
B= 0I4 ( 1R1+ 1R2 )= 4 10-7 44 ( 12 + 14 )
=4 10-7 34 =3 10-7 T
=3
Answer: 3