Two particles X and Y having equal charges are being accelerated through the same potential difference. Thereafter they enter normally in a region of uniform magnetic field and describe circular paths of radii R1 and R2 respectively. The mass ratio of X and Y is :
- ( R1R2 )
- ( R2R1 )
- ( R2R1 )2
- ( R1R2 )2
Answer
(4) ( R1R2 )2
Solution
After acceleration: KE=qV p= 2mqV
Radius in the field: R= mvqB= 2mqVqB
∵ q, V and B are the same ⇒ R m, i.e. m R2
mXmY= ( R1R2 )2
Answer: (4)