Let A = \n [100, 700] N : n is neither a multiple of 3 nor a multiple of 4\. Then the number of elements in A is
- 300
- 310
- 290
- 280
Answer
(1) 300
Solution
Total integers in [100, 700]: 700 - 100 + 1 = 601
Multiples of 3: 102, 105, , 699 200
Multiples of 4: 100, 104, , 700 151
Multiples of 12 (both): 108, 120, , 696 50
n(A) = 601 - (200 + 151 - 50)
= 601 - 301 = 300
Answer: (1)