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JEE Main 2025 (Online) 22nd January Morning ShiftMCQMedium📈 Topic in 5% papers+4−1
Ques. 1JEE Main 2025, 22 January (Morning Shift)

Let A=\1,2,3, ,10\ and B= \ mn:m,n A, m<n and (m,n)=1 \. Then n(B) is equal to :

  1. 29
  2. 31
  3. 37
  4. 36

Answer

(2) 31

Solution

A fraction in lowest terms with denominator n has (n) choices of m; all such fractions are different.

n(B)= n=210 (n)

=1+2+2+4+2+6+4+6+4=31

Answer: (2)

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Ques. 2JEE Main 2026, 22 January (Evening Shift)

Let S be the set of the first 11 natural numbers. Then the number of elements in A = \B S : n(B) 2 and the product of all elements of B is even\ is .

Ques. 3JEE Main 2026, 21 January (Evening Shift)

Let A = \x : |x2 - 10| 6\ and B = \x : |x - 2| > 1\. Then

  1. A B = (- , 1] (2, )
  2. B - A = (- , -4) (-2, 1) (4, )
  3. A - B = [2, 3)
  4. A B = [-4, -2] [3, 4]
Ques. 4JEE Main 2025, 7 April (Evening Shift)

Let A = \( , ) R R : | - 1| 4 and | - 5| 6\ and B = \( , ) R R : 16( - 2)2 + 9( - 6)2 144\. Then

  1. A B
  2. B A
  3. neither A B nor B A
  4. A B = \(x, y) : -4 x 4, -1 y 11\
Ques. 5JEE Main 2025, 4 April (Morning Shift)

Let A = \1, 6, 11, 16, \ and B = \9, 16, 23, 30, \ be the sets consisting of the first 2025 terms of two arithmetic progressions. Then n(A B) is

  1. 3814
  2. 4003
  3. 4027
  4. 3761
Ques. 6JEE Main 2025, 23 January (Evening Shift)

Let A=\(x,y) :|x+y| 3\ and B=\(x,y) :|x|+|y| 3\. If C=\(x,y) :x=0 or y=0\, then (x,y) |x+y| is :

  1. 18
  2. 24
  3. 15
  4. 12

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