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Chemical Bonding and Molecular Structure · Question 28

JEE Main 2025 (Online) 3rd April Evening ShiftMCQEasy📈 Topic in 3% papers+4−1
1

Given below are two statements: In the light of the above statements, choose the correct answer from the options given below

  1. Both Statement I and Statement II are false
  2. Both Statement I and Statement II are true
  3. Statement I is false but Statement II is true
  4. Statement I is true but Statement II is false

Answer

(4) Statement I is true but Statement II is false

Solution

Statement I:

Cotton is cellulose, a polymer of β-D-glucose units; every unit carries three free –OH groups.

These –OH groups form extensive hydrogen bonds with water, so cotton absorbs and holds much water.

Wet cotton clothes take a longer time to dry than wet nylon clothes. Statement I is true.

Statement II:

Nylon is a polyamide; its N–H and C=O groups are mostly used up in strong interchain hydrogen bonds, and the long -(CH2)n- chains are hydrophobic.

Hydrogen bonding of nylon with water is much less than that of cotton.

Statement II is false.

Answer: (4)

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2

A molecule with the formula AX4Y has all its elements from p-block. Element A is rarest, monoatomic, non-radioactive from its group and has the lowest ionization enthalpy value among A, X and Y. Elements X and Y have first and second highest electronegativity values respectively among all the known elements. The shape of the molecule is:

  1. Pentagonal planar
  2. Square pyramidal
  3. Trigonal bipyramidal
  4. Octahedral
JEE Main 2025 (Online) 2nd April Morning Shift
3

Among SO2, NF3, NH3, XeF2, ClF3 and SF4, the hybridization of the molecule with nonzero dipole moment and highest number of lone-pairs of electrons on the central atom is

  1. sp3
  2. dsp2
  3. sp3d2
  4. sp3d
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4

Which among the following molecules is (a) involved in sp3d hybridization, (b) has different bond lengths and (c) has lone pair of electrons on the central atom?

  1. XeF4
  2. XeF2
  3. PF5
  4. SF4
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5

An element 'E' has the ionisation enthalpy value of 374 kJ mol-1. 'E' reacts with elements A, B, C and D with electron gain enthalpy values of −328, −349, −325 and −295 kJ mol-1, respectively. The correct order of the products EA, EB, EC and ED in terms of ionic character is :

  1. EB > EA > EC > ED
  2. EA > EB > EC > ED
  3. ED > EC > EA > EB
  4. ED > EC > EB > EA
JEE Main 2025 (Online) 29th January Morning Shift
6

The sum of sigma ( ) and pi ( ) bonds in Hex-1,3-dien-5-yne is .

JEE Main 2025 (Online) 29th January Morning Shift
7

The molecules having square pyramidal geometry are

  1. BrF5 & PCl5
  2. SbF5 & PCl5
  3. BrF5 & XeOF4
  4. SbF5 & XeOF4
JEE Main 2025 (Online) 28th January Morning Shift
8

Total number of molecules/species from the following which will be paramagnetic is . O2, O2+, O2-, NO, NO2, CO, K2[NiCl4], [Co(NH3)6]Cl3, K2[Ni(CN)4]

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