Let x1, x2, x3, x4 be the solution of the equation 4x4 + 8x3 - 17x2 - 12x + 9 = 0 and (4 + x12 ) (4 + x22 ) (4 + x32 ) (4 + x42 ) = 12516m. Then the value of m is .
Answer
221
Solution
f(x) = 4x4 + 8x3 - 17x2 - 12x + 9 = 4(x - x1)(x - x2)(x - x3)(x - x4)
4 + xr2 = (2i - xr)(-2i - xr)
r=14 (4 + xr2 ) = f(2i)4 f(-2i)4
f(2i) = 64 - 64i + 68 - 24i + 9 = 141 - 88i, f(-2i) = 141 + 88i
(4 + xr2 ) = 1412 + 88216 = 2762516
12516m = 2762516 m = 221
Answer: 221