Let S = \ 2 2 : ( 4 + 4 )x2 + ( 2 )x + ( 6 + 6 ) = 0 has real roots\. If and be the smallest and largest elements of the set S, respectively, then 3 (( - 2)2 + ( - 1)2 ) equals .
Answer
4
Solution
Real roots ⇒ D 0: 2 2 4 ( 4 + 4 ) ( 6 + 6 )
Put t = 2 2 [0, 1]: 4 + 4 = 1 - t2, 6 + 6 = 1 - 3t4
2t (2 - t)(4 - 3t) 3t2 - 12t + 8 0
2 - 2 3 t 2 + 2 3
t 1: S = [2 - 2 3, 1 ] = 2 - 2 3, = 1
3 (( - 2)2 + ( - 1)2 ) = 3 ( 43 + 0 ) = 4
Answer: 4