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Trigonometric Functions · Question 5

JEE Advanced 2024 Paper 1MCQMedium📈 Topic in 17% papers+4−1

Let 2<x< be such that x= -5 11. Then ( 11x2 ) ( 6x- 6x )+ ( 11x2 ) ( 6x+ 6x ) is equal to

11-12 3
11+12 3
11+13 2
11-13 2

Answer

(2) 11+12 3

Solution

Regroup: ( 6x 11x2+ 6x 11x2 )+ ( 6x 11x2- 6x 11x2 )

= x2+ x2

x=- 5 11 in II quadrant x= 116

( x2+ x2 )2=1+ x= 6+ 116, and the sum is positive as x2 ( 4, 2 )

( 11+12 3 )2= 12+2 1112= 6+ 116, so the value is 11+12 3

Answer: (B)

JEE Advanced 2024 Paper 1

Keep practising — Trigonometric Functions

Let f: R R be a function defined by f(x)= cases x2 ( x2 ), & if x 0,\ 0, & if x=0. cases Then which of the following statements is TRUE?

f(x)=0 has infinitely many solutions in the interval [ 11010, ).
f(x)=0 has no solutions in the interval [ 1 , ).
The set of solutions of f(x)=0 in the interval (0, 11010 ) is finite.
f(x)=0 has more than 25 solutions in the interval ( 1 2, 1 ).

JEE Advanced 2024 Paper 2

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All JEE Advanced Mathematics chapters

Class 11Relations and Functions Trigonometric Functions Complex Numbers and Quadratic Equations Permutations and Combinations Binomial Theorem Sequences and Series Conic Sections Limits and Derivatives Statistics

Class 12Relations and Functions (Class 12)Inverse Trigonometric Functions Matrices Determinants Continuity and Differentiability Application of Derivatives Integrals Application of Integrals Differential Equations Vector Algebra Three Dimensional Geometry Probability (Class 12)