Suppose [0, 4 ] is a solution of 4 - 3 = 1. Then is equal to :
- 6 - 6(3 6 - 2)
- 4(3 6 + 2)
- 6 + 6(3 6 + 2)
- 4(3 6 - 2)
Answer
(4) 4(3 6 - 2)
Solution
Put t = 2, so = 1 - t21 + t2 and = 2t1 + t2:
4(1 - t2) - 6t = 1 + t2 5t2 + 6t - 3 = 0
t = -3 2 65
Since [0, 4 ], t 0, so t = 2 6 - 35 and t2 = 33 - 12 625
= 1 - t21 + t2 = 12 6 - 858 - 12 6 = 6 6 - 429 - 6 6
Because (6 6 - 4)(3 6 - 2) = 116 - 24 6 = 4(29 - 6 6), this is 43 6 - 2
Answer: (4)