The area of the region in the first quadrant inside the circle x2 + y2 = 8 and outside the parabola y2 = 2x is equal to :
- 2 - 13
- - 13
- - 23
- 2 - 23
Answer
(3) - 23
Solution
x2 + 2x = 8 x = 2, y = 2: the curves meet at (2, 2)
[figure]
Shaded area (horizontal strips) = 02 y22dy + 22 2 8 - y2 dy
= [ y36 ]02 + [ y2 8 - y2 + 4 -1 y2 2 ]22 2
= 43 + (2 - 2 - )
= - 23
Answer: (3)