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The area (in sq. units) of the region described by \(x, y) : y2 2x, and y 4x - 1 \ is
(1) 932
Meeting points: y22 = y + 14 ⇒ 2y2 - y - 1 = 0 ⇒ y = 1, - 12
[figure]
Shaded strip: from parabola x = y22 (left) to line x = y + 14 (right)
Area = -1/21 ( y + 14 - y22 ) dy = [ y28 + y4 - y36 ]-1/21
= 524 - (- 796 ) = 2796 = 932
Answer: (1)
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