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Differential Equations · Question 2

JEE Main 2026 (Online) 6th April Morning ShiftNumericalMedium📈 Topic in 71% papers+4
1

Let y=y(x) be the solution of the differential equation (x2-x x2-1 )dy + (y (x- x2-1 )-x )dx=0, x 1. If y(1)=1, then the greatest integer less than y ( 5 ) is .

Answer

3

Solution

Dividing by x- x2-1 (>0) : x dy+y dx- xx- x2-1dx=0

1x- x2-1=x+ x2-1 (rationalise; x2- (x2-1 )=1)

d(xy)= (x2+x x2-1 )dx

Integrating ( x x2-1 dx= 13 (x2-1 )3/2) :

xy= x33+ 13 (x2-1 )3/2+C

y(1)=1 1= 13+0+C C= 23

At x= 5 : 5 y= 5 53+ 83+ 23= 5 5+103

y ( 5 )= 5+2 53 5+4.4723 3.16

Greatest integer less than y ( 5 )=3

Answer: 3

JEE Main 2026 (Online) 6th April Morning Shift

Keep practising — Differential Equations

2

Let f: R R be such that f(xy)=f(x)f(y), for all x, y R and f(0) 0. Let g: [1, ) R be a differentiable function such that x2g(x)= 1x (t2f(t)-tg(t) )dt. Then g(2) is equal to :

  1. 138
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3

Let y=y(x) be the solution of the differential equation x ( yx )dy= (y ( yx )-x )dx, y(1)= 2 and let = ( y (e12 )e12 ). Then the number of integral values of p, for which the equation x2+y2-2px+2py+ +2=0 represents a circle of radius r 6, is .

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4

Let f(x) and g(x) be twice differentiable functions satisfying f''(x)=g''(x) for all x R, f'(1)=2g'(1)=4 and g(2)=3f(2)=9. Then f(25)-g(25) is equal to :

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5

Let y=y(x) be the solution of the differential equation ( x)1/2 dy= ( 3x-( x)3/2y )dx, 0<x< 2, y ( 4 )= 6 25. If y ( 3 )= 45 , then 4 equals .

JEE Main 2026 (Online) 5th April Evening Shift
6

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7

Let y=y(x) be the solution of the differential equation : dydx+ ( 6x2+ (3x2+2x3+4 )e-2x (x3+2 ) (2+e-2x ) )y=2+e-2x, x (-1, 2), satisfying y(0)= 32. If y(1)= (2+e-2 ), then is equal to :

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8

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JEE Main 2026 (Online) 4th April Evening Shift
9

If the curve y=f(x) passes through the point (1, e) and satisfies the differential equation dy=y (2+ e x )dx, x>0, then f(e) is equal to :

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10

Let y=y(x) be the solution curve of the differential equation (1+ x) dydx+(y+1) x=0, y(0)=0. If the curve y=y(x) passes through the point ( , -12 ), then a value of is :

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JEE Main 2026 (Online) 2nd April Morning Shift
11

Let x=x(y) be the solution of the differential equation 2y2 dxdy-2xy+x2=0, y>1, x(e)=e. Then x (e2 ) is equal to:

  1. 32e2
  2. 23e2
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JEE Main 2026 (Online) 2nd April Evening Shift

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