Match List I with List II
- A-II, B-IV, C-III, D-I
- A-III, B-II, C-I, D-IV
- A-IV, B-I, C-III, D-II
- A-I, B-IV, C-III, D-II
Answer
(1) A-II, B-IV, C-III, D-I
Solution
Open-chain glucose: OHC-(CHOH)4-CH2OH (–CHO + one 1° –OH + four 2° –OH)
A: no –COOH group ⇒ NaHCO3 gives no reaction ⇒ A–II
B: HNO3 (strong oxidant) oxidises both –CHO and 1° –OH to –COOH ⇒ HOOC-(CHOH)4-COOH, saccharic acid ⇒ B–IV
C: HI/Δ reduces all O-groups ⇒ CH3-(CH2)4-CH3, n-hexane ⇒ C–III
D: Br2 water (mild oxidant) oxidises only –CHO ⇒ HOOC-(CHOH)4-CH2OH, gluconic acid ⇒ D–I
∴ A-II, B-IV, C-III, D-I
Answer: (1)