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The number of tripeptides formed by three different amino acids using each amino acid once is .
6
Let the amino acids be A, B, C. A tripeptide is written from the N-terminal to the C-terminal end, so the order matters:
A–B–C, A–C–B, B–A–C, B–C–A, C–A–B, C–B–A
⇒ Number of tripeptides = 3! = 3 × 2 × 1 = 6
∵ A–B–C (A is N-terminal) and C–B–A (C is N-terminal) are different peptides.
Answer: 6
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