Three capacitors each of capacity 4 are to be connected in such a way that the effective capacitance is 6 . This can be done by
- connecting all of them in series
- connecting them in parallel
- connecting two in series and one in parallel
- connecting two in parallel and one in series
Answer
(3) connecting two in series and one in parallel
Solution
All in series: 43 ; all in parallel: 12
Two in series: 4 44 + 4 = 2
⇒ This combination in parallel with the third: 2 + 4 = 6
(Two in parallel = 8 , in series with the third = 8 412 = 83 )
∴ Two in series and one in parallel give 6 .
Answer: (3)