Identical charges (-q) are placed at each corner of a cube of side b then electrostatic potential energy of charge (+q) which is placed at centre of cube will be
- -4 2q2 0 b
- -8 2q2 0 b
- -4q2 3 0 b
- 8 2q24 0 b
Answer
(3) -4q2 3 0 b
Solution
Distance of each corner from the centre = 3b2 (half the body diagonal)
Potential energy of +q with the 8 charges:
U = 8 14 0 (+q)(-q) 3b/2
= - 16q24 3 0 b
U = -4q2 3 0 b
Answer: (3)