A thin spherical shell is charged by some source. The potential difference between the two points C and P (in V) shown in the figure is: (Take 14 0 = 9 109 SI units) [figure]
- 3 105
- 1 105
- 0.5 105
- Zero
Answer
(4) Zero
Solution
For a charged thin spherical shell, the electric field inside is zero, so the potential is the same at every point inside and on the shell:
VC = VP = 14 0 qR
= 9 109 10-63 10-2 = 3 105 V
VC - VP = 0
Answer: (4)