A 12 pF capacitor is connected to a 50 V battery, the electrostatic energy stored in the capacitor in nJ is
- 15
- 7.5
- 0.3
- 150
Answer
(1) 15
Solution
Energy stored in a capacitor:
U = 12CV2
= 12 12 10-12 (50)2
= 1.5 10-8 J
= 15 nJ
Answer: (1)
A 12 pF capacitor is connected to a 50 V battery, the electrostatic energy stored in the capacitor in nJ is
(1) 15
Energy stored in a capacitor:
U = 12CV2
= 12 12 10-12 (50)2
= 1.5 10-8 J
= 15 nJ
Answer: (1)
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