For a transparent prism, if the angle of minimum deviation is equal to its refracting angle, the refractive index n of the prism satisfies.
- n 2
- 2 < n < 2
- 1 < n < 2
- 2 < n < 2 2
Answer
(2) 2 < n < 2
Solution
n = ( A + m2 ) ( A2 ); with m = A:
n = A A2 = 2 A2
At minimum deviation the angle of incidence is i = A + m2 = A, and i < 90 0 < A2 < 45
1 2 < A2 < 1
2 < n < 2
Answer: (2)