The magnitudes of power of a biconvex lens (refractive index 1.5) and that of a plano-concave lens (refractive index = 1.7) are same. If the curvature of plano-concave lens exactly matches with the curvature of back surface of the biconvex lens, then ratio of radius of curvature of front and back surface of the biconvex lens is
- 2 : 5
- 5 : 2
- 12 : 5
- 5 : 12
Answer
(2) 5 : 2
Solution
Let the radii of the front and back surfaces of the biconvex lens be R1 and R2.
Biconvex lens: P1 = (1.5 - 1) ( 1R1 + 1R2 ) = 0.5 ( 1R1 + 1R2 )
Plano-concave lens (curved surface of radius R2): |P2| = (1.7 - 1) 1R2 = 0.7R2
|P1| = |P2|
0.5R1 + 0.5R2 = 0.7R2
0.5R1 = 0.2R2
R1R2 = 0.50.2 = 52
Answer: (2)