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Amines · Question 2

JEE Advanced 2025 Paper 1MatchingMedium📈 Topic in 17% papers+4−1
1

The major products obtained from the reactions in List-II are the reactants for the named reactions mentioned in List-I. Match each entry in List-I with the appropriate entry in List-II and choose the correct option.

  1. P → 2; Q → 4; R → 1; S → 3
  2. P → 2; Q → 3; R → 4; S → 1
  3. P → 5; Q → 3; R → 4; S → 2
  4. P → 5; Q → 4; R → 2; S → 1

Answer

(2) P → 2; Q → 3; R → 4; S → 1

Solution

(1) Étard reaction gives benzaldehyde, which has no α-H: reactant for Cannizzaro reaction, so S → 1.

[figure] [(ii) H3O+](i) CrO2Cl2/CS2 [figure]

(2) Acid → acid chloride → amide → (dehydration) nitrile: reactant for Stephen reaction, so P → 2.

[figure] PCl5 [figure] NH3 [figure]

P4O10, [figure]

(3) Reduction, then diazotisation gives the diazonium salt: reactant for Sandmeyer reaction, so Q → 3.

[figure] Fe, HCl [figure] NaNO2, HCl, 273-278 K [figure] Cl-

(4) Side-chain chlorination and hydrolysis give benzaldehyde; Tollens' oxidation gives benzoic acid; then acid chloride and amide. Benzamide is the reactant for Hoffmann bromamide degradation, so R → 4.

[figure] Cl2/h [figure] H2O [figure]

Tollens' reagent [figure]

SO2Cl2 [figure] NH3 [figure]

(5) Protection, nitration and deprotection give p-nitroaniline, which is not needed.

[figure] (CH3CO)2O [figure] HNO3, H2SO4 [figure] aq. NaOH [figure]

Answer: (B)

JEE Advanced 2025 Paper 1

Keep practising — Amines

2

For the reaction sequence given below, the correct statement(s) is(are) [figure]

  1. Both X and Y are oxygen containing compounds.
  2. Y on heating with CHCl3/KOH forms isocyanide.
  3. Z reacts with Hinsberg’s reagent.
  4. Z is an aromatic primary amine.
JEE Advanced 2025 Paper 2

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