A particle of mass m is projected with a velocity 'u' making an angle of 30 with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height h is :
- mu3 2 g
- zero
- 32 mu2g
- 316 mu3g
Answer
(4) 316 mu3g
Solution
[figure]
At the top, velocity is horizontal (u 30 ); its line is at perpendicular distance h from O.
L=m(u 30 ) h, with h= u2 2 30 2g= u28g
L=m 3u2 u28g= 316 mu3g
Answer: (4)