If x ( ( e1-e ) ( 1e- x1+x ) )x= , then the value of e 1+ e equals :
- e-2
- e2
- e
- e-1
Answer
(3) e
Solution
1 form: [1+h(x)]x=e x h(x)
Base = e1-e (1+x)-exe(1+x)=1+ e(1-e)(1+x)
x h(x) e1-e e = e1-e
e 1+ e = e/(1-e)1/(1-e)=e
Answer: (3)
If x ( ( e1-e ) ( 1e- x1+x ) )x= , then the value of e 1+ e equals :
(3) e
1 form: [1+h(x)]x=e x h(x)
Base = e1-e (1+x)-exe(1+x)=1+ e(1-e)(1+x)
x h(x) e1-e e = e1-e
e 1+ e = e/(1-e)1/(1-e)=e
Answer: (3)
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