If the function f(x) = ex (e x - x - 1 ) + e( x + x) - x x - x is continuous at x = 0, then the value of f(0) is equal to
- 23
- 12
- 2
- 32
Answer
(4) 32
Solution
For continuity at x = 0: f(0) = x 0 f(x)
f(x) = ex e x - x - 1 x - x + e( x + x) - x x - x
First part: put t = x - x 0
ex et - 1t 1 1 = 1
Second part: x = x + x33 + x - x = x33 +
ddx e( x + x) = x = 1 + x22 +
e( x + x) = x + x36 +
e( x + x) - x x - x x3/6x3/3 = 12
f(0) = 1 + 12 = 32
Answer: (4)