A body of mass M thrown horizontally with velocity v from the top of the tower of height H touches the ground at a distance of 100 m from the foot of the tower. A body of mass 2 M thrown at a velocity v2 from the top of the tower of height 4H will touch the ground at a distance of m.
Answer
100
Solution
Horizontal projection: x = u 2hg (independent of mass)
First body: 100 = v 2Hg
Second body: x' = v2 2(4H)g = v2 2 2Hg
= v 2Hg = 100 m
Answer: 100