In a hydrogen like ion, the energy difference between the 2nd excitation energy state and ground is 108.8 eV. The atomic number of the ion is:
- 1
- 4
- 3
- 2
Answer
(3) 3
Solution
Second excited state ⇒ n = 3; ground state ⇒ n = 1.
For a hydrogen-like ion: En = - 13.6 Z2n2 eV
E = 13.6 Z2 ( 112 - 132 ) = 13.6 Z2 89
⇒ 13.6 Z2 89 = 108.8
⇒ Z2 = 108.8 913.6 8 = 9
∴ Z = 3
Answer: (3)