The energy of an electron in an orbit of the Bohr's atom is -0.04E0 eV where E0 is the ground state energy. If L is the angular momentum of the electron in this orbit and h is the Planck's constant, then 2 Lh is :
- 6
- 2
- 5
- 4
Answer
(3) 5
Solution
In Bohr's model: En = - E0n2 (here E0 = 13.6, the magnitude of the ground state energy in eV)
- E0n2 = -0.04E0
n2 = 10.04 = 25 n = 5
Bohr's quantisation: L = nh2
2 Lh = n = 5
Answer: (3)