Atoms · Question 20

The ratio of momentum of the photons of the 1st and 2nd line of Balmer series of Hydrogen atoms is / . The possible values of and are :

1. 27 and 20
2. 3 and 16
3. 5 and 36
4. 20 and 27

In the hydrogen atom, the electron makes a transition from the higher orbit (i) to a lower orbit (f). The ratio of the radius of the orbits is given by ri:rf=16:4. The wavelength of photon emitted due to this transition is nm. (Given Rydberg constant = 1.0973 107 /m)

1. 121
2. 242
3. 486
4. 974

In Rutherford's alpha-particle scattering experiment, only a few alpha particles rebound back because Choose the correct answer from the options given below :

1. A, B Only
2. B, E Only
3. C, D Only
4. A, C, E Only

Angular momentum of an electron in a hydrogen atom is 3h , then the energy of the electron is eV.

1. -1.51
2. -0.85
3. -0.38
4. -0.28

Using Bohr's model, calculate the ratio of the magnetic fields generated due to the motion of the electrons in the 2nd and 4th orbits of hydrogen atom .

Two electrons are moving in orbits of two hydrogen-like atoms with speeds 3 105 m/s and 2.5 105 m/s respectively. If the radii of these orbits are nearly same then the possible order of energy states are respectively.

1. 8 and 10
2. 10 and 12
3. 9 and 8
4. 6 and 5

In hydrogen atom spectrum, (R Rydberg's constant) Choose the correct answer from the options given below :

1. A, B Only
2. B, D Only
3. A, B and D Only
4. A, B and C Only

A 7.9 MeV -particle scatters from a target material of atomic number 79. From the given data the estimated diameter of nuclei of the target material is (approximately) m. [ 14 0 = 9 109 N m2/C2 . and electron charge . = 1.6 10-19 C ]

1. 2.88 10-14
2. 5.76 10-14
3. 1.44 10-13
4. 1.69 10-12

The smallest wavelength of Lyman series is 91 nm. The difference between the largest wavelengths of Paschen and Balmer series is nearly nm.

1. 1784
2. 1875
3. 1217
4. 1550

If an alpha particle with energy 7.7 MeV is bombarded on a thin gold foil, the closest distance from nucleus it can reach is m. (Atomic number of gold = 79 and 14 0 = 9 109 in SI units)

1. 2.95 10-16
2. 3.85 10-14
3. 2.95 10-14
4. 3.85 10-16