In Young's double slit experiment, if the separation between coherent sources is halved and the distance of the screen from the coherent sources is doubled, then the fringe width becomes :
- half
- four times
- one-fourth
- double
Answer
(2) four times
Solution
Fringe width, = Dd
New separation d' = d2, new distance D' = 2D
' = (2D)d/2
= 4 Dd = 4
Fringe width becomes four times.
Answer: (2)