In a reaction, A + B product, rate is doubled when the concentration of B is doubled, and rate increases by a factor of 8 when the concentrations of both the reactants (A and B) are doubled, rate law for the reaction can be written as
- rate = k[A][B]2
- rate = k[A]2[B]2
- rate = k[A][B]
- rate = k[A]2[B]
Answer
(4) rate = k[A]2[B]
Solution
Let rate = k[A]x[B]y.
doubling [B] alone doubles the rate 2y = 2 y = 1
doubling both increases the rate 8 times 2x+y = 8 = 23 x + y = 3
x = 2
rate = k[A]2[B]
Answer: (4)