For the reaction, N2 + 3H2 2NH3, if d[NH3]dt = 2 10-4 mol L-1 s-1, the value of -d[H2]dt would be
- 4 10-4 mol L-1 s-1
- 6 10-4 mol L-1 s-1
- 1 10-4 mol L-1 s-1
- 3 10-4 mol L-1 s-1
Answer
(4) 3 10-4 mol L-1 s-1
Solution
Rate = - 13 d[H2]dt = 12 d[NH3]dt
- d[H2]dt = 32 2 10-4
= 3 10-4 mol L-1 s-1
Answer: (4)