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Integrals

JEE Main 2024 (Online) 1st February Evening ShiftNumericalEasy📈 Topic in 9% papers+4
Ques. 1JEE Main 2024, 1 February (Evening Shift)

Let f:(0, ) and F(x)= 0x tf(t) dt. If F (x2 )=x4+x5, then r=112f (r2 ) is equal to .

Answer

219

Solution

F (x2 )=x4+x5 (t)=t2+t5/2

'(t)=2t+ 52t3/2=t f(t)

( Newton–Leibnitz rule)

f(t)=2+ 52 t f (r2 )=2+ 52r

r=112f (r2 )=24+ 52 12 132=24+195=219

Answer: 219

Keep practising — Integrals

Ques. 2JEE Main 2024, 31 January (Morning Shift)

If the integral 525 0 2 2x 112x (1+ 52x ) 12dx is equal to (n 2-64 ), then n is equal to .

Ques. 3JEE Main 2024, 31 January (Morning Shift)

Let f : R R be a function defined by f(x)= 4x4x+2 and M= f(a)f(1-a)x 4(x(1-x))dx, N= f(a)f(1-a) 4(x(1-x))dx; a 12. If M= N, , N, then the least value of 2+ 2 is equal to .

Ques. 4JEE Main 2024, 31 January (Evening Shift)

Let f, g:(0, ) R be two functions defined by f(x)= -xx (|t|-t2 )e-t2dt and g(x)= 0x2t1/2e-tdt. Then, the value of 9 (f ( e9 )+g ( e9 ) ) is equal to :

  1. 10
  2. 9
  3. 8
  4. 6
Ques. 5JEE Main 2024, 31 January (Evening Shift)

| 120 3 0 x2 x x 4x+ 4xdx | is equal to .

Ques. 6JEE Main 2024, 30 January (Morning Shift)

The value of n k=1n n3 (n2+k2 ) (n2+3k2 ) is :

  1. 8(2 3+3)
  2. (2 3+3) 24
  3. 13 8(4 3+3)
  4. 13(2 3-3) 8
Ques. 7JEE Main 2024, 30 January (Morning Shift)

The value of 9 09 [ 10xx+1 ]dx, where [t] denotes the greatest integer less than or equal to t, is .

Ques. 8JEE Main 2024, 30 January (Evening Shift)

Let f: R R be a function defined by f(x)= x (1+x4 )1/4, and g(x)=f(f(f(f(x)))). Then, 18 0 2 5x2g(x) dx is equal to

  1. 36
  2. 33
  3. 39
  4. 42
Ques. 9JEE Main 2024, 30 January (Evening Shift)

Let y=f(x) be a thrice differentiable function in (-5,5). Let the tangents to the curve y=f(x) at (1,f(1)) and (3,f(3)) make angles /6 and /4, respectively with positive x-axis. If 27 13 ( (f'(t) )2+1 )f''(t) dt= + 3 where , are integers, then the value of + equals

  1. 26
  2. -16
  3. 36
  4. -14
Ques. 10JEE Main 2024, 30 January (Evening Shift)

Let f: R R be defined as f(x)=ae2x+bex+cx. If f(0)=-1, f' ( e2 )=21 and 0 e4(f(x)-cx) dx= 392, then the value of |a+b+c| equals

  1. 16
  2. 12
  3. 8
  4. 10
Ques. 11JEE Main 2024, 29 January (Morning Shift)

For x (- 2, 2 ), if y(x)= cosec x+ xcosec x x+ x 2x dx, and x ( 2 )-y(x)=0 then y ( 4 ) is equal to

  1. - 1 2 -1 ( 1 2 )
  2. -1 ( 1 2 )
  3. 12 -1 ( 1 2 )
  4. 1 2 -1 (- 12 )

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