The smallest wavelength of Lyman series is 91 nm. The difference between the largest wavelengths of Paschen and Balmer series is nearly nm.
- 1784
- 1875
- 1217
- 1550
Answer
(3) 1217
Solution
1 = R ( 1n12 - 1n22 )
Smallest wavelength of Lyman series (n1 = 1, n2 = ): 1 = R 1R = 91 nm
Largest wavelength of Balmer series (3 2): 1 B = R ( 14 - 19 ) = 5R36
B = 365 91 = 655.2 nm
Largest wavelength of Paschen series (4 3): 1 P = R ( 19 - 116 ) = 7R144
P = 1447 91 = 1872 nm
P - B = 1872 - 655.2
= 1216.8 nm 1217 nm
Answer: (3)